(X^2-9)/(x^3-4x)

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Solution for (X^2-9)/(x^3-4x) equation: 


D( x )

x^3-(4*x) = 0

x^3-(4*x) = 0

x^3-(4*x) = 0

x^3-4*x = 0

x^3-4*x = 0

x*(x^2-4) = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x = 0

x = 0

x in (-oo:-2) U (-2:0) U (0:2) U (2:+oo)

(X^2-9)/(x^3-(4*x)) = 0

(X^2-9)/(x^3-4*x) = 0

x^3-4*x = 0

x*(x^2-4) = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x*(x-2)*(x+2) = 0

(X^2-9)/(x*(x-2)*(x+2)) = 0

x belongs to the empty set

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